PSLE The students at a sports meet are divided in Team A and Team B. The ratio of the number of boys to girls in Team A is 3 : 2. The ratio of the number of boys to girls in Team B is 3 : 1. There are 4 times as many students in Team B as in Team A. There are 168 more boys in Team B than Team A. What is the total number of girls?
Team A |
Team B |
5 u |
4x5 = 20 u |
Boys |
Girls |
Boys |
Girls |
3 u |
2 u |
3x5 = 15 u |
1x5 = 5 u
|
Total number of students in Team A
= 3 u + 2 u
= 5 u
Total number of students in Team B
= 4 x 5 u
= 20 u
The total number of students in Team B is repeated.
Use LCM to make the total number of students in Team B the same.
LCM of 20 and 4 is 20.
Number of more boys in Team B than Team A
= 15 u - 3 u
= 12 u
12 u = 168
1 u = 168 ÷ 12 = 14
Total number of girls
= 2 u + 5 u
= 7 u
= 7 x 14
= 98
Answer(s): 98