PSLE The contestants at a contest are divided in Team A and Team B. The ratio of the number of boys to girls in Team A is 2 : 1. The ratio of the number of boys to girls in Team B is 2 : 3. There are 5 times as many contestants in Team B as in Team A. There are 48 more boys in Team B than Team A. What is the total number of girls?
Team A |
Team B |
3 u |
5x3 = 15 u |
Boys |
Girls |
Boys |
Girls |
2 u |
1 u |
2x3 = 6 u |
3x3 = 9 u
|
Total number of contestants in Team A
= 2 u + 1 u
= 3 u
Total number of contestants in Team B
= 5 x 3 u
= 15 u
The total number of contestants in Team B is repeated.
Use LCM to make the total number of contestants in Team B the same.
LCM of 15 and 5 is 15.
Number of more boys in Team B than Team A
= 6 u - 2 u
= 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Total number of girls
= 1 u + 9 u
= 10 u
= 10 x 12
= 120
Answer(s): 120