PSLE The contestants at a contest are divided in Team A and Team B. The ratio of the number of boys to girls in Team A is 7 : 1. The ratio of the number of boys to girls in Team B is 5 : 7. There are 3 times as many contestants in Team B as in Team A. There are 6 more boys in Team B than Team A. What is the total number of girls?
Team A |
Team B |
8 u |
12x2 = 24 u |
Boys |
Girls |
Boys |
Girls |
7 u |
1 u |
5x2 = 10 u |
7x2 = 14 u
|
Total number of contestants in Team A
= 7 u + 1 u
= 8 u
Total number of contestants in Team B
= 3 x 8 u
= 24 u
The total number of contestants in Team B is repeated.
Use LCM to make the total number of contestants in Team B the same.
LCM of 24 and 12 is 24.
Number of more boys in Team B than Team A
= 10 u - 7 u
= 3 u
3 u = 6
1 u = 6 ÷ 3 = 2
Total number of girls
= 1 u + 14 u
= 15 u
= 15 x 2
= 30
Answer(s): 30