PSLE The contestants at a contest are divided in Team A and Team B. The ratio of the number of girls to boys in Team A is 3 : 2. The ratio of the number of girls to boys in Team B is 1 : 2. There are 3 times as many contestants in Team B as in Team A. There are 12 less girls in Team A than Team B. What is the total number of contestants in Team A?
Team A |
Team B |
5 u |
3x5 = 15 u |
Girls |
Boys |
Girls |
Boys |
3 u |
2 u |
1x5 = 5 u |
2x5 = 10 u
|
Total number of contestants in Team A
= 3 u + 2 u
= 5 u
Total number of contestants in Team B
= 3 x 5 u
= 15 u
The total number of contestants in Team B is repeated.
Use LCM to make the total number of contestants in Team B the same.
LCM of 15 and 3 is 15.
Number of less girls in Team A than Team B
= 5 u - 3 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Total number of contestants in Team A
= 3 u + 2 u
= 5 u
= 5 x 6
= 30
Answer(s): 30