PSLE The contestants at a contest are divided in Team A and Team B. The ratio of the number of boys to girls in Team A is 3 : 2. The ratio of the number of boys to girls in Team B is 1 : 3. There are 4 times as many contestants in Team B as in Team A. There are 8 more boys in Team B than Team A. What is the total number of contestants?
Team A |
Team B |
5 u |
4x5 = 20 u |
Boys |
Girls |
Boys |
Girls |
3 u |
2 u |
1x5 = 5 u |
3x5 = 15 u
|
Total number of contestants in Team A
= 3 u + 2 u
= 5 u
Total number of contestants in Team B
= 4 x 5 u
= 20 u
The total number of contestants in Team B is repeated.
Use LCM to make the total number of contestants in Team B the same.
LCM of 20 and 4 is 20.
Number of more boys in Team B than Team A
= 5 u - 3 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Total number of contestants
= 3 u + 2 u + 5 u + 15 u
= 25 u
= 25 x 4
= 100
Answer(s): 100