PSLE The contestants at a contest are divided in Team A and Team B. The ratio of the number of boys to girls in Team A is 4 : 1. The ratio of the number of boys to girls in Team B is 2 : 1. There are 3 times as many contestants in Team B as in Team A. There are 42 less boys in Team A than Team B. What is the total number of contestants in Team A?
Team A |
Team B |
5 u |
3x5 = 15 u |
Boys |
Girls |
Boys |
Girls |
4 u |
1 u |
2x5 = 10 u |
1x5 = 5 u
|
Total number of contestants in Team A
= 4 u + 1 u
= 5 u
Total number of contestants in Team B
= 3 x 5 u
= 15 u
The total number of contestants in Team B is repeated.
Use LCM to make the total number of contestants in Team B the same.
LCM of 15 and 3 is 15.
Number of less boys in Team A than Team B
= 10 u - 4 u
= 6 u
6 u = 42
1 u = 42 ÷ 6 = 7
Total number of contestants in Team A
= 4 u + 1 u
= 5 u
= 5 x 7
= 35
Answer(s): 35