PSLE The contestants at a contest are divided in Group A and Group B. The ratio of the number of girls to boys in Group A is 7 : 1. The ratio of the number of girls to boys in Group B is 5 : 1. There are 3 times as many contestants in Group B as in Group A. There are 143 more girls in Group B than Group A. What is the total number of boys?
Group A |
Group B |
8 u |
6x4 = 24 u |
Girls |
Boys |
Girls |
Boys |
7 u |
1 u |
5x4 = 20 u |
1x4 = 4 u
|
Total number of contestants in Group A
= 7 u + 1 u
= 8 u
Total number of contestants in Group B
= 3 x 8 u
= 24 u
The total number of contestants in Group B is repeated.
Use LCM to make the total number of contestants in Group B the same.
LCM of 24 and 6 is 24.
Number of more girls in Group B than Group A
= 20 u - 7 u
= 13 u
13 u = 143
1 u = 143 ÷ 13 = 11
Total number of boys
= 1 u + 4 u
= 5 u
= 5 x 11
= 55
Answer(s): 55