PSLE The contestants at a contest are divided in Team A and Team B. The ratio of the number of boys to girls in Team A is 2 : 1. The ratio of the number of boys to girls in Team B is 5 : 1. There are 4 times as many contestants in Team B as in Team A. There are 72 more boys in Team B than Team A. What is the total number of contestants?
Team A |
Team B |
3 u |
6x2 = 12 u |
Boys |
Girls |
Boys |
Girls |
2 u |
1 u |
5x2 = 10 u |
1x2 = 2 u
|
Total number of contestants in Team A
= 2 u + 1 u
= 3 u
Total number of contestants in Team B
= 4 x 3 u
= 12 u
The total number of contestants in Team B is repeated.
Use LCM to make the total number of contestants in Team B the same.
LCM of 12 and 6 is 12.
Number of more boys in Team B than Team A
= 10 u - 2 u
= 8 u
8 u = 72
1 u = 72 ÷ 8 = 9
Total number of contestants
= 2 u + 1 u + 10 u + 2 u
= 15 u
= 15 x 9
= 135
Answer(s): 135