PSLE The pupils at a camp are divided in Team A and Team B. The ratio of the number of boys to girls in Team A is 4 : 1. The ratio of the number of boys to girls in Team B is 3 : 1. There are 4 times as many pupils in Team B as in Team A. There are 66 less boys in Team A than Team B. What is the total number of pupils in Team A?
Team A |
Team B |
5 u |
4x5 = 20 u |
Boys |
Girls |
Boys |
Girls |
4 u |
1 u |
3x5 = 15 u |
1x5 = 5 u
|
Total number of pupils in Team A
= 4 u + 1 u
= 5 u
Total number of pupils in Team B
= 4 x 5 u
= 20 u
The total number of pupils in Team B is repeated.
Use LCM to make the total number of pupils in Team B the same.
LCM of 20 and 4 is 20.
Number of less boys in Team A than Team B
= 15 u - 4 u
= 11 u
11 u = 66
1 u = 66 ÷ 11 = 6
Total number of pupils in Team A
= 4 u + 1 u
= 5 u
= 5 x 6
= 30
Answer(s): 30