PSLE The contestants at a contest are divided in Group A and Group B. The ratio of the number of boys to girls in Group A is 5 : 4. The ratio of the number of boys to girls in Group B is 5 : 1. There are 2 times as many contestants in Group B as in Group A. There are 150 less boys in Group A than Group B. What is the total number of contestants in Group A?
Group A |
Group B |
9 u |
6x3 = 18 u |
Boys |
Girls |
Boys |
Girls |
5 u |
4 u |
5x3 = 15 u |
1x3 = 3 u
|
Total number of contestants in Group A
= 5 u + 4 u
= 9 u
Total number of contestants in Group B
= 2 x 9 u
= 18 u
The total number of contestants in Group B is repeated.
Use LCM to make the total number of contestants in Group B the same.
LCM of 18 and 6 is 18.
Number of less boys in Group A than Group B
= 15 u - 5 u
= 10 u
10 u = 150
1 u = 150 ÷ 10 = 15
Total number of contestants in Group A
= 5 u + 4 u
= 9 u
= 9 x 15
= 135
Answer(s): 135