PSLE The contestants at a contest are divided in Team A and Team B. The ratio of the number of girls to boys in Team A is 3 : 2. The ratio of the number of girls to boys in Team B is 9 : 1. There are 4 times as many contestants in Team B as in Team A. There are 60 less girls in Team A than Team B. What is the total number of contestants in Team A?
Team A |
Team B |
5 u |
10x2 = 20 u |
Girls |
Boys |
Girls |
Boys |
3 u |
2 u |
9x2 = 18 u |
1x2 = 2 u
|
Total number of contestants in Team A
= 3 u + 2 u
= 5 u
Total number of contestants in Team B
= 4 x 5 u
= 20 u
The total number of contestants in Team B is repeated.
Use LCM to make the total number of contestants in Team B the same.
LCM of 20 and 10 is 20.
Number of less girls in Team A than Team B
= 18 u - 3 u
= 15 u
15 u = 60
1 u = 60 ÷ 15 = 4
Total number of contestants in Team A
= 3 u + 2 u
= 5 u
= 5 x 4
= 20
Answer(s): 20