PSLE The contestants at a contest are divided in Group A and Group B. The ratio of the number of boys to girls in Group A is 3 : 1. The ratio of the number of boys to girls in Group B is 7 : 1. There are 4 times as many contestants in Group B as in Group A. There are 165 more boys in Group B than Group A. What is the total number of girls?
Group A |
Group B |
4 u |
8x2 = 16 u |
Boys |
Girls |
Boys |
Girls |
3 u |
1 u |
7x2 = 14 u |
1x2 = 2 u
|
Total number of contestants in Group A
= 3 u + 1 u
= 4 u
Total number of contestants in Group B
= 4 x 4 u
= 16 u
The total number of contestants in Group B is repeated.
Use LCM to make the total number of contestants in Group B the same.
LCM of 16 and 8 is 16.
Number of more boys in Group B than Group A
= 14 u - 3 u
= 11 u
11 u = 165
1 u = 165 ÷ 11 = 15
Total number of girls
= 1 u + 2 u
= 3 u
= 3 x 15
= 45
Answer(s): 45