PSLE A stationery kiosk is having a book sale.
The 1st book is at 10% discount.
The 2nd book is at 40% discount.
The price of the 2nd book should be equal or lower than the price of the 1st book.
Shannon and Caden each bought two books at the sale.
- Shannon's books were priced at $4 and $19. How much did she pay for them?
- Caden paid a total of $37.80 for his two books. He paid $12.60 more for the 1st book than the 2nd book. What was the price of the 2nd book before discount?
|
1st book |
2nd book |
Total amount |
Original price
|
100% $19 |
100% $4 |
|
Discount |
- 10% |
- 40% |
|
Sale price |
90% |
60% |
? |
(a)
Selling price of the 1st book
= 90% x 19
=
90100 x 19
= $17.10
Selling price of 2nd book
= 60% x 4
=
60100 x 4
= $2.40
Total amount that Shannon paid
= 17.10 + 2.40
= $19.50
|
1st book |
2nd book |
Total amount |
Original price |
100% |
100% |
|
Discount |
- 10% |
- 40% |
|
Sale price |
90%
|
60%
|
|
Compare 1st book and 2nd book |
1 u + $12.60 |
1 u |
$37.80 |
(b)
Sale price of the 1st book = 1 u + 12.60
Sale price of the 2nd book = 1 u
Total amount that Caden paid
= 1 u + 12.60 + 1 u
= 2 u + 12.60
2 u + 12.60 = 37.80
2 u = 37.80 - 12.60
2 u = 25.20
1 u = 25.20 ÷ 2 = 12.60
Sale price of the 2nd book = $12.60
60% of the price = $12.60
100% of the price =
12.6060 x 100 = $21
Selling price of the 2nd book before discount = $21
Answer(s): (a) $19.50; (b) $21