PSLE Howard had green pens and blue pens for sale. He sold 300 green pens. 40% of the pens sold were blue.
- How many green pens and blue pens did Howard sell altogether?
- He sold 50% of his pens. 60% of the pens left unsold were green. How many blue pens did Howard have at first?
| |
Green |
Blue |
Total |
Total in percent |
| Before |
6 u |
4 u |
10 u |
100% |
| Change |
- 60%
- 3 u |
- 40%
- 2 u |
- 100%
- 5 u |
- 50% |
| After |
60%
3 u |
40%
2 u |
100%
5 u |
50%
|
40% =
40100 =
25 Total number of pens sold = 5 u
Number of blue pens sold = 2 u
Number of green pens sold
= 5 u - 2 u
= 3 u
3 u = 300
1 u = 300 ÷ 3 = 100
Total number of pens sold
= 5 u
= 5 x 100
= 500
(b)
Percent of the pens left unsold = 100% - 50% = 50% 50% of the pens that were sold = 5 u 50% of the pens that were left unsold = 5 u Percent of the pens left unsold that were green = 60%
Percent of the pens left unsold that were blue = 100% - 60% = 40%
Number of the pens left unsold that were blue
= 40% x 5 u
=
40100 x 5 u
= 2 u
Number of blue pens that Howard had at first
= 2 u + 2 u
= 4 u
= 4 x 100
= 400
Answer(s): (a) 500; (b) 400
