PSLE In a school, 60% of the members in Reading Club and 75% of the members in Computer Club are boys. Both clubs have the same number of girls. The Computer Club has 30 more boys than the Reading Club. How many boys are there altogether?
|
Reading Club |
Computer Club |
Types |
Boys |
Girls |
Boys |
Girls |
Comparing the boys and the girls in each club |
3x1 |
2x1 |
3x2 |
1x2 |
Comparing the girls in 2 clubs |
|
1 |
|
1 |
|
3 u |
2 u |
6 u |
2 u |
60% =
60100 =
35 Fraction of the members in Reading Club that are girls
= 1 -
35 =
25 75% =
75100 =
34 Fraction of the members in Computer club that are girls
= 1 -
34 =
14 The number of girls in both clubs is the same. Make the numerators the same. LCM of 2 and 1 is 2.
2x15x1 of the members in Reading Club =
1x24x2 of the members in Computer Club
25of the members in Reading Club =
28 of the members in Computer Club
Number of more boys in Computer Club than Reading Club
= 6 u - 3 u
= 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Total number of boys
= 3 u + 6 u
= 9 u
= 9 x 10
= 90
Answer(s): 90