PSLE In a school, 40% of the members in Reading Club and 90% of the members in Computer Club are boys. Both clubs have the same number of girls. The Computer Club has 125 more boys than the Reading Club. How many boys are there altogether?
|
Reading Club |
Computer Club |
Types |
Boys |
Girls |
Boys |
Girls |
Comparing the boys and the girls in each club |
2x1 |
3x1 |
9x3 |
1x3 |
Comparing the girls in 2 clubs |
|
1 |
|
1 |
|
2 u |
3 u |
27 u |
3 u |
40% =
40100 =
25 Fraction of the members in Reading Club that are girls
= 1 -
25 =
35 90% =
90100 =
910 Fraction of the members in Computer club that are girls
= 1 -
910 =
110 The number of girls in both clubs is the same. Make the numerators the same. LCM of 3 and 1 is 3.
3x15x1 of the members in Reading Club =
1x310x3 of the members in Computer Club
35of the members in Reading Club =
330 of the members in Computer Club
Number of more boys in Computer Club than Reading Club
= 27 u - 2 u
= 25 u
25 u = 125
1 u = 125 ÷ 25 = 5
Total number of boys
= 2 u + 27 u
= 29 u
= 29 x 5
= 145
Answer(s): 145