PSLE The students of a test are divided equally into two groups. In the first group, there are 40 less girls than boys. In the second group, there are 8 more girls than boys. 40% of all the students are girls. How many students are girls?
|
First group |
Second group |
Total |
Comparison 1 |
50% |
50% |
100% |
Comparison 2 |
Boys (more) |
Girls (less)
|
Boys (less)
|
Girls (more) |
|
|
1 u + 40 |
1 u |
1 u + 16 |
1 u + 16 + 8 |
|
Comparison 3 |
Total girls |
Total boys |
|
|
40% |
60% |
100% |
Number of students in the first group and the second group is equal.
Percentage of students who are boys
= 100% - 40%
= 60%
Percentage of more boys than girls
= 60% - 40%
= 20%
Total number of boys
= 1 u + 40 + 1 u + 16
= 2 u + 56
Total number of girls
= 1 u + 1 u + 16 + 8
= 2 u + 24
Number of boys more than girls
= 56 - 24
= 32
20% of the students = 32
1% of the students = 32 ÷ 20 = 1.6
40% of the students
= 40 x 1.6
= 64
Number of students that are girls = 64
Answer(s): 64