PSLE Peter kept his brown and silver balls in two boxes. The ratio of the number of brown to silver balls in the first box was 1 : 8 and it was 1 : 2 in the second box. The two boxes contained the same number of balls. What fraction of Peter's balls were brown balls?
First box |
Second box |
1x9 9 u |
1x9 9 u |
9x1 |
3x3 |
Brown |
Silver |
Brown |
Silver |
1x1 |
8x1 |
1x3 |
2x3 |
1 u |
8 u |
3 u |
6 u |
The total number of balls in the first box and the second box is the same. Make the total number of balls in each box the same. LCM of 9 and 3 is 9.
Total number of brown balls
= 1 u + 3 u
= 4 u
Total number of balls
= 9 u + 9 u
= 18 u
Fraction of Peter's balls that were brown balls
=
418 =
29 Answer(s):
29