PSLE Riordan kept his gold and red beads in two boxes. The ratio of the number of gold to red beads in the first box was 1 : 4 and it was 3 : 4 in the second box. The two boxes contained the same number of beads. What fraction of Riordan's beads were red beads?
First box |
Second box |
1x35 35 u |
1x35 35 u |
5x7 |
7x5 |
Gold |
Red |
Gold |
Red |
1x7 |
4x7 |
3x5 |
4x5 |
7 u |
28 u |
15 u |
20 u |
The total number of beads in the first box and the second box is the same. Make the total number of beads in each box the same.
LCM of 5 and 7 is 35.
Total number of red beads
= 28 u + 20 u
= 48 u
Total number of beads
= 35 u + 35 u
= 70 u
Fraction of Riordan's beads that were red beads
=
4870 =
2435 Answer(s):
2435