PSLE Valen kept his blue and red coins in two boxes. The ratio of the number of blue to red coins in the first box was 1 : 2 and it was 1 : 5 in the second box. The two boxes contained the same number of coins. What fraction of Valen's coins were red coins?
First box |
Second box |
1x6 6 u |
1x6 6 u |
3x2 |
6x1 |
Blue |
Red |
Blue |
Red |
1x2 |
2x2 |
1x1 |
5x1 |
2 u |
4 u |
1 u |
5 u |
The total number of coins in the first box and the second box is the same. Make the total number of coins in each box the same.
LCM of 3 and 6 is 6.
Total number of red coins
= 4 u + 5 u
= 9 u
Total number of coins
= 6 u + 6 u
= 12 u
Fraction of Valen's coins that were red coins
=
912 =
34 Answer(s):
34