PSLE Ahmad kept his black and gold beads in two boxes. The ratio of the number of black to gold beads in the first box was 1 : 5 and it was 1 : 2 in the second box. The two boxes contained the same number of beads. What fraction of Ahmad's beads were gold beads?
First box |
Second box |
1x6 6 u |
1x6 6 u |
6x1 |
3x2 |
Black |
Gold |
Black |
Gold |
1x1 |
5x1 |
1x2 |
2x2 |
1 u |
5 u |
2 u |
4 u |
The total number of beads in the first box and the second box is the same. Make the total number of beads in each box the same.
LCM of 6 and 3 is 6.
Total number of gold beads
= 5 u + 4 u
= 9 u
Total number of beads
= 6 u + 6 u
= 12 u
Fraction of Ahmad's beads that were gold beads
=
912 =
34 Answer(s):
34