PSLE Tim kept his red and brown beads in two boxes. The ratio of the number of red to brown beads in the first box was 2 : 3 and it was 1 : 9 in the second box. The two boxes contained the same number of beads. What fraction of Tim's beads were red beads?
First box |
Second box |
1x10 10 u |
1x10 10 u |
5x2 |
10x1 |
Red |
Brown |
Red |
Brown |
2x2 |
3x2 |
1x1 |
9x1 |
4 u |
6 u |
1 u |
9 u |
The total number of beads in the first box and the second box is the same. Make the total number of beads in each box the same. LCM of 5 and 10 is 10.
Total number of red beads
= 4 u + 1 u
= 5 u
Total number of beads
= 10 u + 10 u
= 20 u
Fraction of Tim's beads that were red beads
=
520 =
14 Answer(s):
14