PSLE Michael kept his purple and green balls in two boxes. The ratio of the number of purple to green balls in the first box was 3 : 7 and it was 1 : 4 in the second box. The two boxes contained the same number of balls. What fraction of Michael's balls were purple balls?
First box |
Second box |
1x10 10 u |
1x10 10 u |
10x1 |
5x2 |
Purple |
Green |
Purple |
Green |
3x1 |
7x1 |
1x2 |
4x2 |
3 u |
7 u |
2 u |
8 u |
The total number of balls in the first box and the second box is the same. Make the total number of balls in each box the same. LCM of 10 and 5 is 10.
Total number of purple balls
= 3 u + 2 u
= 5 u
Total number of balls
= 10 u + 10 u
= 20 u
Fraction of Michael's balls that were purple balls
=
520 =
14 Answer(s):
14