PSLE Will kept his grey and red beads in two boxes. The ratio of the number of grey to red beads in the first box was 1 : 2 and it was 3 : 4 in the second box. The two boxes contained the same number of beads. What fraction of Will's beads were red beads?
First box |
Second box |
1x21 21 u |
1x21 21 u |
3x7 |
7x3 |
Grey |
Red |
Grey |
Red |
1x7 |
2x7 |
3x3 |
4x3 |
7 u |
14 u |
9 u |
12 u |
The total number of beads in the first box and the second box is the same. Make the total number of beads in each box the same.
LCM of 3 and 7 is 21.
Total number of red beads
= 14 u + 12 u
= 26 u
Total number of beads
= 21 u + 21 u
= 42 u
Fraction of Will's beads that were red beads
=
2642 =
1321 Answer(s):
1321