PSLE Albert kept his brown and gold balls in two boxes. The ratio of the number of brown to gold balls in the first box was 1 : 5 and it was 1 : 2 in the second box. The two boxes contained the same number of balls. What fraction of Albert's balls were gold balls?
First box |
Second box |
1x6 6 u |
1x6 6 u |
6x1 |
3x2 |
Brown |
Gold |
Brown |
Gold |
1x1 |
5x1 |
1x2 |
2x2 |
1 u |
5 u |
2 u |
4 u |
The total number of balls in the first box and the second box is the same. Make the total number of balls in each box the same.
LCM of 6 and 3 is 6.
Total number of gold balls
= 5 u + 4 u
= 9 u
Total number of balls
= 6 u + 6 u
= 12 u
Fraction of Albert's balls that were gold balls
=
912 =
34 Answer(s):
34