PSLE At a basketball match, 50% of the tickets were sold at full price and 30% of the tickets at half price. The remaining 120 tickets were given away free. The total amount of money collected was $14820. What was the full price of the ticket?
Percentage of the tickets given free
= 100% - 50% - 30%
= 20%
20% → 120
1% → 120 ÷ 20 = 6
Number of tickets sold at full price
= 50% of the tickets
= 50 x 6
= 300
Number of tickets sold at half price
= 30% of the tickets
= 30 x 6
= 180
|
Full price |
Half price |
Free |
Total |
Number |
300 |
180 |
120 |
|
Value |
2 u |
1 u |
|
|
Total value |
600 u |
180 u |
|
780 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 300 x 2 u + 180 x 1 u
= 600 u + 180 u
= 780 u
780 u = 14820
1 u = 14820 ÷ 780 = 19
Full price of the ticket
= 2 u
= 2 x 19
= $38
Answer(s): $38