PSLE At a basketball match, 45% of the tickets were sold at full price and 10% of the tickets at half price. The remaining 450 tickets were given away free. The total amount of money collected was $24000. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 45% - 10%
= 45%
45% → 450
1% → 450 ÷ 45 = 10
Number of tickets sold at full price
= 45% of the tickets
= 45 x 10
= 450
Number of tickets sold at half price
= 10% of the tickets
= 10 x 10
= 100
|
Full price |
Half price |
Free |
Total |
Number |
450 |
100 |
450 |
|
Value |
2 u |
1 u |
|
|
Total value |
900 u |
100 u |
|
1000 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 450 x 2 u + 100 x 1 u
= 900 u + 100 u
= 1000 u
1000 u = 24000
1 u = 24000 ÷ 1000 = 24
Price of the ticket at half price
= 1 u
= $24
Answer(s): $24