PSLE At a basketball match, 40% of the tickets were sold at full price and 55% of the tickets at half price. The remaining 30 tickets were given away free. The total amount of money collected was $10530. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 40% - 55%
= 5%
5% → 30
1% → 30 ÷ 5 = 6
Number of tickets sold at full price
= 40% of the tickets
= 40 x 6
= 240
Number of tickets sold at half price
= 55% of the tickets
= 55 x 6
= 330
|
Full price |
Half price |
Free |
Total |
Number |
240 |
330 |
30 |
|
Value |
2 u |
1 u |
|
|
Total value |
480 u |
330 u |
|
810 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 240 x 2 u + 330 x 1 u
= 480 u + 330 u
= 810 u
810 u = 10530
1 u = 10530 ÷ 810 = 13
Price of the ticket at half price
= 1 u
= $13
Answer(s): $13