PSLE At a basketball match, 40% of the tickets were sold at full price and 40% of the tickets at half price. The remaining 200 tickets were given away free. The total amount of money collected was $16800. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 40% - 40%
= 20%
20% → 200
1% → 200 ÷ 20 = 10
Number of tickets sold at full price
= 40% of the tickets
= 40 x 10
= 400
Number of tickets sold at half price
= 40% of the tickets
= 40 x 10
= 400
|
Full price |
Half price |
Free |
Total |
Number |
400 |
400 |
200 |
|
Value |
2 u |
1 u |
|
|
Total value |
800 u |
400 u |
|
1200 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 400 x 2 u + 400 x 1 u
= 800 u + 400 u
= 1200 u
1200 u = 16800
1 u = 16800 ÷ 1200 = 14
Price of the ticket at half price
= 1 u
= $14
Answer(s): $14