PSLE At a basketball match, 30% of the tickets were sold at full price and 15% of the tickets at half price. The remaining 440 tickets were given away free. The total amount of money collected was $9600. What was the full price of the ticket?
Percentage of the tickets given free
= 100% - 30% - 15%
= 55%
55% → 440
1% → 440 ÷ 55 = 8
Number of tickets sold at full price
= 30% of the tickets
= 30 x 8
= 240
Number of tickets sold at half price
= 15% of the tickets
= 15 x 8
= 120
|
Full price |
Half price |
Free |
Total |
Number |
240 |
120 |
440 |
|
Value |
2 u |
1 u |
|
|
Total value |
480 u |
120 u |
|
600 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 240 x 2 u + 120 x 1 u
= 480 u + 120 u
= 600 u
600 u = 9600
1 u = 9600 ÷ 600 = 16
Full price of the ticket
= 2 u
= 2 x 16
= $32
Answer(s): $32