PSLE At a soccer match, 50% of the tickets were sold at full price and 45% of the tickets at half price. The remaining 40 tickets were given away free. The total amount of money collected was $17400. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 50% - 45%
= 5%
5% → 40
1% → 40 ÷ 5 = 8
Number of tickets sold at full price
= 50% of the tickets
= 50 x 8
= 400
Number of tickets sold at half price
= 45% of the tickets
= 45 x 8
= 360
|
Full price |
Half price |
Free |
Total |
Number |
400 |
360 |
40 |
|
Value |
2 u |
1 u |
|
|
Total value |
800 u |
360 u |
|
1160 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 400 x 2 u + 360 x 1 u
= 800 u + 360 u
= 1160 u
1160 u = 17400
1 u = 17400 ÷ 1160 = 15
Price of the ticket at half price
= 1 u
= $15
Answer(s): $15