PSLE At a basketball match, 55% of the tickets were sold at full price and 15% of the tickets at half price. The remaining 60 tickets were given away free. The total amount of money collected was $5750. What was the full price of the ticket?
Percentage of the tickets given free
= 100% - 55% - 15%
= 30%
30% → 60
1% → 60 ÷ 30 = 2
Number of tickets sold at full price
= 55% of the tickets
= 55 x 2
= 110
Number of tickets sold at half price
= 15% of the tickets
= 15 x 2
= 30
|
Full price |
Half price |
Free |
Total |
Number |
110 |
30 |
60 |
|
Value |
2 u |
1 u |
|
|
Total value |
220 u |
30 u |
|
250 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 110 x 2 u + 30 x 1 u
= 220 u + 30 u
= 250 u
250 u = 5750
1 u = 5750 ÷ 250 = 23
Full price of the ticket
= 2 u
= 2 x 23
= $46
Answer(s): $46