PSLE At a basketball match, 40% of the tickets were sold at full price and 50% of the tickets at half price. The remaining 60 tickets were given away free. The total amount of money collected was $14820. What was the full price of the ticket?
Percentage of the tickets given free
= 100% - 40% - 50%
= 10%
10% → 60
1% → 60 ÷ 10 = 6
Number of tickets sold at full price
= 40% of the tickets
= 40 x 6
= 240
Number of tickets sold at half price
= 50% of the tickets
= 50 x 6
= 300
|
Full price |
Half price |
Free |
Total |
Number |
240 |
300 |
60 |
|
Value |
2 u |
1 u |
|
|
Total value |
480 u |
300 u |
|
780 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 240 x 2 u + 300 x 1 u
= 480 u + 300 u
= 780 u
780 u = 14820
1 u = 14820 ÷ 780 = 19
Full price of the ticket
= 2 u
= 2 x 19
= $38
Answer(s): $38