PSLE At a basketball match, 55% of the tickets were sold at full price and 40% of the tickets at half price. The remaining 40 tickets were given away free. The total amount of money collected was $31200. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 55% - 40%
= 5%
5% → 40
1% → 40 ÷ 5 = 8
Number of tickets sold at full price
= 55% of the tickets
= 55 x 8
= 440
Number of tickets sold at half price
= 40% of the tickets
= 40 x 8
= 320
|
Full price |
Half price |
Free |
Total |
Number |
440 |
320 |
40 |
|
Value |
2 u |
1 u |
|
|
Total value |
880 u |
320 u |
|
1200 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 440 x 2 u + 320 x 1 u
= 880 u + 320 u
= 1200 u
1200 u = 31200
1 u = 31200 ÷ 1200 = 26
Price of the ticket at half price
= 1 u
= $26
Answer(s): $26