PSLE At a basketball match, 30% of the tickets were sold at full price and 10% of the tickets at half price. The remaining 420 tickets were given away free. The total amount of money collected was $9310. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 30% - 10%
= 60%
60% → 420
1% → 420 ÷ 60 = 7
Number of tickets sold at full price
= 30% of the tickets
= 30 x 7
= 210
Number of tickets sold at half price
= 10% of the tickets
= 10 x 7
= 70
|
Full price |
Half price |
Free |
Total |
Number |
210 |
70 |
420 |
|
Value |
2 u |
1 u |
|
|
Total value |
420 u |
70 u |
|
490 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 210 x 2 u + 70 x 1 u
= 420 u + 70 u
= 490 u
490 u = 9310
1 u = 9310 ÷ 490 = 19
Price of the ticket at half price
= 1 u
= $19
Answer(s): $19