PSLE At a soccer match, 20% of the tickets were sold at full price and 55% of the tickets at half price. The remaining 225 tickets were given away free. The total amount of money collected was $20520. What was the full price of the ticket?
Percentage of the tickets given free
= 100% - 20% - 55%
= 25%
25% → 225
1% → 225 ÷ 25 = 9
Number of tickets sold at full price
= 20% of the tickets
= 20 x 9
= 180
Number of tickets sold at half price
= 55% of the tickets
= 55 x 9
= 495
|
Full price |
Half price |
Free |
Total |
Number |
180 |
495 |
225 |
|
Value |
2 u |
1 u |
|
|
Total value |
360 u |
495 u |
|
855 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 180 x 2 u + 495 x 1 u
= 360 u + 495 u
= 855 u
855 u = 20520
1 u = 20520 ÷ 855 = 24
Full price of the ticket
= 2 u
= 2 x 24
= $48
Answer(s): $48