PSLE At a basketball match, 35% of the tickets were sold at full price and 10% of the tickets at half price. The remaining 440 tickets were given away free. The total amount of money collected was $8960. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 35% - 10%
= 55%
55% → 440
1% → 440 ÷ 55 = 8
Number of tickets sold at full price
= 35% of the tickets
= 35 x 8
= 280
Number of tickets sold at half price
= 10% of the tickets
= 10 x 8
= 80
|
Full price |
Half price |
Free |
Total |
Number |
280 |
80 |
440 |
|
Value |
2 u |
1 u |
|
|
Total value |
560 u |
80 u |
|
640 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 280 x 2 u + 80 x 1 u
= 560 u + 80 u
= 640 u
640 u = 8960
1 u = 8960 ÷ 640 = 14
Price of the ticket at half price
= 1 u
= $14
Answer(s): $14