PSLE At a basketball match, 20% of the tickets were sold at full price and 25% of the tickets at half price. The remaining 440 tickets were given away free. The total amount of money collected was $8840. What was the full price of the ticket?
Percentage of the tickets given free
= 100% - 20% - 25%
= 55%
55% → 440
1% → 440 ÷ 55 = 8
Number of tickets sold at full price
= 20% of the tickets
= 20 x 8
= 160
Number of tickets sold at half price
= 25% of the tickets
= 25 x 8
= 200
|
Full price |
Half price |
Free |
Total |
Number |
160 |
200 |
440 |
|
Value |
2 u |
1 u |
|
|
Total value |
320 u |
200 u |
|
520 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 160 x 2 u + 200 x 1 u
= 320 u + 200 u
= 520 u
520 u = 8840
1 u = 8840 ÷ 520 = 17
Full price of the ticket
= 2 u
= 2 x 17
= $34
Answer(s): $34