PSLE At a basketball match, 40% of the tickets were sold at full price and 20% of the tickets at half price. The remaining 120 tickets were given away free. The total amount of money collected was $4200. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 40% - 20%
= 40%
40% → 120
1% → 120 ÷ 40 = 3
Number of tickets sold at full price
= 40% of the tickets
= 40 x 3
= 120
Number of tickets sold at half price
= 20% of the tickets
= 20 x 3
= 60
|
Full price |
Half price |
Free |
Total |
Number |
120 |
60 |
120 |
|
Value |
2 u |
1 u |
|
|
Total value |
240 u |
60 u |
|
300 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 120 x 2 u + 60 x 1 u
= 240 u + 60 u
= 300 u
300 u = 4200
1 u = 4200 ÷ 300 = 14
Price of the ticket at half price
= 1 u
= $14
Answer(s): $14