PSLE At a soccer match, 25% of the tickets were sold at full price and 60% of the tickets at half price. The remaining 120 tickets were given away free. The total amount of money collected was $10560. What was the full price of the ticket?
Percentage of the tickets given free
= 100% - 25% - 60%
= 15%
15% → 120
1% → 120 ÷ 15 = 8
Number of tickets sold at full price
= 25% of the tickets
= 25 x 8
= 200
Number of tickets sold at half price
= 60% of the tickets
= 60 x 8
= 480
|
Full price |
Half price |
Free |
Total |
Number |
200 |
480 |
120 |
|
Value |
2 u |
1 u |
|
|
Total value |
400 u |
480 u |
|
880 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 200 x 2 u + 480 x 1 u
= 400 u + 480 u
= 880 u
880 u = 10560
1 u = 10560 ÷ 880 = 12
Full price of the ticket
= 2 u
= 2 x 12
= $24
Answer(s): $24