PSLE At a basketball match, 40% of the tickets were sold at full price and 20% of the tickets at half price. The remaining 80 tickets were given away free. The total amount of money collected was $3400. What was the full price of the ticket?
Percentage of the tickets given free
= 100% - 40% - 20%
= 40%
40% → 80
1% → 80 ÷ 40 = 2
Number of tickets sold at full price
= 40% of the tickets
= 40 x 2
= 80
Number of tickets sold at half price
= 20% of the tickets
= 20 x 2
= 40
|
Full price |
Half price |
Free |
Total |
Number |
80 |
40 |
80 |
|
Value |
2 u |
1 u |
|
|
Total value |
160 u |
40 u |
|
200 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 80 x 2 u + 40 x 1 u
= 160 u + 40 u
= 200 u
200 u = 3400
1 u = 3400 ÷ 200 = 17
Full price of the ticket
= 2 u
= 2 x 17
= $34
Answer(s): $34