PSLE At a basketball match, 45% of the tickets were sold at full price and 20% of the tickets at half price. The remaining 140 tickets were given away free. The total amount of money collected was $9680. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 45% - 20%
= 35%
35% → 140
1% → 140 ÷ 35 = 4
Number of tickets sold at full price
= 45% of the tickets
= 45 x 4
= 180
Number of tickets sold at half price
= 20% of the tickets
= 20 x 4
= 80
|
Full price |
Half price |
Free |
Total |
Number |
180 |
80 |
140 |
|
Value |
2 u |
1 u |
|
|
Total value |
360 u |
80 u |
|
440 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 180 x 2 u + 80 x 1 u
= 360 u + 80 u
= 440 u
440 u = 9680
1 u = 9680 ÷ 440 = 22
Price of the ticket at half price
= 1 u
= $22
Answer(s): $22