PSLE At a basketball match, 60% of the tickets were sold at full price and 20% of the tickets at half price. The remaining 40 tickets were given away free. The total amount of money collected was $3080. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 60% - 20%
= 20%
20% → 40
1% → 40 ÷ 20 = 2
Number of tickets sold at full price
= 60% of the tickets
= 60 x 2
= 120
Number of tickets sold at half price
= 20% of the tickets
= 20 x 2
= 40
|
Full price |
Half price |
Free |
Total |
Number |
120 |
40 |
40 |
|
Value |
2 u |
1 u |
|
|
Total value |
240 u |
40 u |
|
280 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 120 x 2 u + 40 x 1 u
= 240 u + 40 u
= 280 u
280 u = 3080
1 u = 3080 ÷ 280 = 11
Price of the ticket at half price
= 1 u
= $11
Answer(s): $11