PSLE At a soccer match, 30% of the tickets were sold at full price and 55% of the tickets at half price. The remaining 60 tickets were given away free. The total amount of money collected was $9200. What was the price of the ticket at half price?
Percentage of the tickets given free
= 100% - 30% - 55%
= 15%
15% → 60
1% → 60 ÷ 15 = 4
Number of tickets sold at full price
= 30% of the tickets
= 30 x 4
= 120
Number of tickets sold at half price
= 55% of the tickets
= 55 x 4
= 220
|
Full price |
Half price |
Free |
Total |
Number |
120 |
220 |
60 |
|
Value |
2 u |
1 u |
|
|
Total value |
240 u |
220 u |
|
460 u |
Cost of 1 full price ticket = 2 u
Cost of 1 half price ticket = 1 u
Total amount collected
= 120 x 2 u + 220 x 1 u
= 240 u + 220 u
= 460 u
460 u = 9200
1 u = 9200 ÷ 460 = 20
Price of the ticket at half price
= 1 u
= $20
Answer(s): $20