PSLE A correction tape costs $3 more than a highlighter. The total cost of 7 such correction tapes is $4
p.
- Express the cost of 14 such correction tapes in terms of p.
- Express the cost of the highlighter in terms of p.
(a)
Number of sets of 7 correction tapes in 14 correction tapes
= 14 ÷ 7
= 2
Cost of 14 correction tapes
= 2 x 4
p = $8
p (b)
Cost of a correction tape
= 4
p ÷ 7
= $
4p7 Cost of a highlighter
=
4p7 - 3
=
4p7 -
217= $(
4p - 217)
Answer(s): (a) $8
p; (b) $(
4p - 217) or $
4p - 217 or $(
4p7 - 3)