PSLE The perimeter of figure EFGHJ is (5
q + 20) cm. The perimeter of square EFGH is 12 cm.
- Find the perimeter of triangle EHJ in terms of q.
- The perimeter of figure EFGHJ is 55 cm. What is the value of q? Give your answer in cm.
(a)
Length of the square
= 12 ÷ 4
= 3 cm
Total lengths of EF, FG and GH
= 3 x 3
= 9 cm
Perimeter of triangle EHJ
= 5
q + 20 - 3 - 3
= (5
q + 14) cm
(b)
5
q + 20 = 55
5
q = 55 - 20
5
q = 35
q = 35 ÷ 5 = 7
Value of
q = 7 cm
Answer(s): (a) (5
q + 14) cm; (b) 7 cm