PSLE The perimeter of figure HJKLM is (10
c + 22) cm. The perimeter of square HJKL is 24 cm.
- Find the perimeter of triangle HLM in terms of c.
- The perimeter of figure HJKLM is 92 cm. What is the value of c? Give your answer in cm.
(a)
Length of the square
= 24 ÷ 4
= 6 cm
Total lengths of HJ, JK and KL
= 3 x 6
= 18 cm
Perimeter of triangle HLM
= 10
c + 22 - 6 - 6
= (10
c + 10) cm
(b)
10
c + 22 = 92
10
c = 92 - 22
10
c = 70
c = 70 ÷ 10 = 7
Value of
c = 7 cm
Answer(s): (a) (10
c + 10) cm; (b) 7 cm