PSLE The perimeter of figure EFGHJ is (4
y + 13) cm. The perimeter of square EFGH is 8 cm.
- Find the perimeter of triangle EHJ in terms of y.
- The perimeter of figure EFGHJ is 45 cm. What is the value of y? Give your answer in cm.
(a)
Length of the square
= 8 ÷ 4
= 2 cm
Total lengths of EF, FG and GH
= 3 x 2
= 6 cm
Perimeter of triangle EHJ
= 4
y + 13 - 2 - 2
= (4
y + 9) cm
(b)
4
y + 13 = 45
4
y = 45 - 13
4
y = 32
y = 32 ÷ 4 = 8
Value of
y = 8 cm
Answer(s): (a) (4
y + 9) cm; (b) 8 cm