PSLE The perimeter of figure TUVWX is (9
d + 25) cm. The perimeter of square TUVW is 12 cm.
- Find the perimeter of triangle TWX in terms of d.
- The perimeter of figure TUVWX is 88 cm. What is the value of d? Give your answer in cm.
(a)
Length of the square
= 12 ÷ 4
= 3 cm
Total lengths of TU, UV and VW
= 3 x 3
= 9 cm
Perimeter of triangle TWX
= 9
d + 25 - 3 - 3
= (9
d + 19) cm
(b)
9
d + 25 = 88
9
d = 88 - 25
9
d = 63
d = 63 ÷ 9 = 7
Value of
d = 7 cm
Answer(s): (a) (9
d + 19) cm; (b) 7 cm