PSLE The perimeter of figure HJKLM is (10
x + 15) cm. The perimeter of square HJKL is 12 cm.
- Find the perimeter of triangle HLM in terms of x.
- The perimeter of figure HJKLM is 65 cm. What is the value of x? Give your answer in cm.
(a)
Length of the square
= 12 ÷ 4
= 3 cm
Total lengths of HJ, JK and KL
= 3 x 3
= 9 cm
Perimeter of triangle HLM
= 10
x + 15 - 3 - 3
= (10
x + 9) cm
(b)
10
x + 15 = 65
10
x = 65 - 15
10
x = 50
x = 50 ÷ 10 = 5
Value of
x = 5 cm
Answer(s): (a) (10
x + 9) cm; (b) 5 cm